(Medium #40) Combination Sum II
Problem
Given a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sums to target.
Each number in candidates may only be used once in the combination.
Note:
- All numbers (including
target) will be positive integers.
- The solution set must not contain duplicate combinations.
Example 1:
Input: candidates = [10,1,2,7,6,1,5], target = 8,
A solution set is:
[
[1, 7],
[1, 2, 5],
[2, 6],
[1, 1, 6]
]
Example 2:
Input: candidates = [2,5,2,1,2], target = 5,
A solution set is:
[
[1,2,2],
[5]
Given a collection of candidate numbers (
candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sums to target.
Each number in
candidates may only be used once in the combination.
Note:
- All numbers (including
target) will be positive integers. - The solution set must not contain duplicate combinations.
Example 1:
Input: candidates =[10,1,2,7,6,1,5], target =8, A solution set is: [ [1, 7], [1, 2, 5], [2, 6], [1, 1, 6] ]
Example 2:
Input: candidates = [2,5,2,1,2], target = 5, A solution set is: [ [1,2,2], [5]
My solution
class Solution(object):
def combinationSum2(self, candidates, target):
candidates.sort()
res = []
self.dfs(candidates, 0, target, [], res)
return res
def dfs(self, cand, start, target, path, res):
if target < 0: # backtracking
return
if target == 0:
res.append(path)
return
for i in range(start, len(cand)):
if i > start and cand[i-1] == cand[i]:
continue
else:
self.dfs(cand, i+1, target-cand[i], path+[cand[i]], res)
Runtime: 100ms, Memory: 13.8MB
def combinationSum2(self, candidates, target):
candidates.sort()
res = []
self.dfs(candidates, 0, target, [], res)
return res
def dfs(self, cand, start, target, path, res):
if target < 0: # backtracking
return
if target == 0:
res.append(path)
return
for i in range(start, len(cand)):
if i > start and cand[i-1] == cand[i]:
continue
else:
self.dfs(cand, i+1, target-cand[i], path+[cand[i]], res)
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